1. A car traveling at 49ft/sec49ft/sec decelerates at a constant 4ft/sec24ft/sec

Question

1. A car traveling at 49ft/sec49ft/sec decelerates at a constant 4ft/sec24ft/sec2. How many feet does the car travel before coming to a complete stop?

2. A stone is thrown straight up from the edge of a roof, 800 feet above the ground, at a speed of 20 feet per second.

A. Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 5 seconds later?

B. At what time does the stone hit the ground?

C. What is the velocity of the stone when it hits the ground?

Explanation / Answer

1)a = difference in velocity / difference in time.
4= 49 / difference in time.

it's 49/4=12.25 seconds.

to find the distance, we have to integrate the velocity function from 0 to 12.25 seconds.

velocity = 49 - 4t
integral of that is -2t^2 + 49t. from 12.25,

it's 300.125feet. That's how far it travelled.

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