The discharge of a river (the volume of water it caries per time) can be calcula
ID: 2857307 • Letter: T
Question
The discharge of a river (the volume of water it caries per time) can be calculated as:
Below is a cross section of the Colorado River at Lee's Ferry on February 14, 1956.
On this particular day you can see that the top of the river is located at 15 ft above zero. The average bottom of the river (represented by the dotted line) is at -5 ft. This makes the total river depth 20 ft.
The width, measured across the top of the river profile, is 390 ft.
On that day the river velocity was measured at 8 ft/sec.
*What is the width of the river (in ft)?
*What was the average depth of the river on February 14, 1956 (in ft)?
*The discharge of the river on February 14, 1956 was 4760 ft3/sec (cfs=cubic feet per second). Based on the width, depth and dischage, what was the velocity of the river on this day in 1956 (in ft3/sec)?
Hint: You need to rearrange the formula above to calculate the velocity.
Explanation / Answer
width of the river is 390 ft
depth of the river is 20 ft
4760 = width x depth x velocity
=> velocity = 0.61 ft/s
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