same problem different give. I only need CORRECT answers. A rectangular tank tha

Question

same problem different give. I only need CORRECT answers.

A rectangular tank that is 3 meters long, 2 meters wide and 6 meters deep is filled with a rubbing alcohol that has density 786 kilograms per cubic meter. In each part below, assume that the tank is initially full, and that gravity is 9.8 meters per second squared. Your answers must include the correct units (a) How much work is done pumping all of the liquid out over the top of the tank? units b) How much work is done pumping all of the liquid out of a spout 2 meters above the top of the tank? ) How much workisdone pumping all of the liquid out of units (c) How much work is done pumping two-thirds of the liquid out over the top of the tank? units d) How much work is done pumping two-thirds of the liquid out of a spout 2 meters above the top of the tank? units

Explanation / Answer

part (a)

dimension of the tank is

long=3m

wide =2m

deep=6m

therefore,volume of the tank is

V=2*3*6=36m3

and the given density is=786 kg/m3

therefore mass of the tank is

MASS=VOLUME*DENSITY

M=36*786kg

and acceleration due to the gravity is=9.8m/s2

so,the force acting on the tank is=M*9.8

F=36*786*9.8 Newton

and the work done is

Workdone=force *Displacement

(a)

so,in pumping all the liquid out over the tank

displacement is =6m

so,

Workdone=36*786*9.8*6 joule

(b)

in pumping 2m above the tank

displacement=2m

so,

W=36*786*9.8*2 joule

(c)

in pumping 2/3rd of the liquied out over the tank

initial volume of the liquid is=36m3

so,2/3rd volume of the luquid =24m3

mass=24*786kg

force =24*786*9.8 Newton

therefore workdone in moving this amount of luquid out over the tank is

W=24*786*9.8*6 joule

(d)

in pumping 2/3rd of the luquid 2m obove the tank is

W=24*786*9.8*2 joule

part (b)

all the answer will be same because deepness in this case is also 6 meter and volume is same for both the tank.

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