1. Where on Fig.4.2 (below) would one predict a concentrati Why? Let\'s look at
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1. Where on Fig.4.2 (below) would one predict a concentrati Why? Let's look at it: "Figure 4.2" is part of a regional seismic line shot over the Brent area of the North Sea. 1200 250 300 350 400 450 500 e 30 seco esso soo P S0 00 seso soo 8950 sve ves0 100 Lliummal 10. Ram41 SQ1 00 was passed --NNNAN 3.0. 3.1 3.5 Use a colored pencil to mark the boundaries of the "main" geological features; and a simple indication of how oil would flow or pool – using these facts: "Point A" -- put this at 2.3 Two-way seconds (Y-Axis) and 8400 Shotpoint (X-Axis) "Point B" -- put this at 2.8 Two-way seconds (Y-Axis) and 8600 Shotpoint (X-Axis) We will assume that the sediment that is typical of “Point A" (and drapes over the irregular underlying sedimentary rock is Clay-rich, therefore can act as a barrier to oil migration; and that at "Point B" is Sand-rich, therefore can allow oil to migrate through or accumulate (reservoir) within it. Oil will migrate upwards through the "B" sands until the "A" clays block it. Put a big "X" on the spot that you interpret as the most likely oil find. Then, summarize your logic (a sketch of your scenario might help): 2. How deep to drill to it? For now, assume that "1.0" at the top of the plot is the sea-floor; therefore one would need to drill through the underlying sediment to reach the predicted oil pool. Given that sound travels about 2.6 kilometers per second in this type of sedimentary rock, how deep is the oil below that sea-floor level “10” (give in “two-way" seconds, then both in Meters and in Feet)? [IMPORTANT NOTE: This seismic plot, like all such plots, uses a scale of Two-Way (echo) travel time = the roundtrip time for sound to go down and return. Therefore, you must use the "one- way" travel time to get actual distance. Accidentally using "2-way" is a very common mistake ...)Explanation / Answer
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Volume of reservoir = (length*breath*height)
Volume of oil = (length*breath*height)* porosity {Since oil would be in pore spaces only}
Recoverable oil = recovery factor * (length*breath*height)* porosity
Length = 200*(25/1000)
Breadth = 10*1.60934
Thickness = 0.2
Volume of reservoir = 200*(25/1000)*10*1.60934*0.2
= 16.0934km3
Volume of oil = 16.0934* (15/100)
=2.41401km3 or (This is equal to estimated volume of oil in the reservoir)
2.41401km3 = 2.41401 x 109m3
2.41401 x 109m3 = 2.41401 x 109 x 6.29 = 15.18 x 109 US bbl oil {1m3 = 6.29 US bbl oil}
15.18 x 109/ (50 x 106) = 15,180 million US bbl oil {This is equal to estimated volume of oil in the reservoir}
Recoverable oil = 2.41401*(2/3)
=1.60934km3 0r 1.60934 x 109m3
1.60934 x 109m3 = 10.1227 x 109 US bbl oil
Value of oil = 10.1227 x 109 x 80 = 8.09816 x 1011 = 809.816 billion USD
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