find the direction in the xy-plane in which the following functions have zero ch
ID: 2847467 • Letter: F
Question
find the direction in the xy-plane in which the following functions have zero change at the given point. i need help for number 60,f(x,y)=x^2-4y^2-8, p(4,1,4)
Explanation / Answer
The directional change for a function can be calculated by finding the directional derivative at a point in a given direction which can be found by finding the gradient of the function at the point and then finding the dot product of the gradient with the given direction vector.... so the gradient of given f(x) will be del(f(x,y))=(partial derivative w.r.t x)i+(partial derivative w.r.t y)
so gradient =(2x)i-(8y)j
thus at the point (1,2,4)we have gradient =2i-16j
Let the required direction be xi+yj in the xy plane
so according to question (2i-16j).(xi+yj)=0
=> 2x-16y=0
=>x=8y
Thus the vector will be xi+yj=8yi+yj
where i and j are unit vectors
Removing the common y we have 8i+j as the required answer because all other vectors will be parallel to the answer vector for integral y values
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