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During its climb to cruise altitude, a B-52H pilot radios a 32,000 ft. density a

ID: 284671 • Letter: D

Question


During its climb to cruise altitude, a B-52H pilot radios a 32,000 ft. density altitude. What would the density, temperature and pressure of air be at die standard atmospheric conditions? If at that point, the ambient temperature is 434 deg. Rankine, what is the temperature altitude? What is the actual pressure? What is the pressure altitude? Construct a table with the following columns, from left to right: Geometric altitude, geopotential altitude, temperature, pressure, and density. Do this from 0 to 36,000 ft. in steps of 2.000; this is a warmer atmosphere where temperature and pressure at sea level are 88 deg Fahrenheit and 2.140 psf. respectively. Temperature diminishes with altitude at the same rate as the standard atmosphere?

Explanation / Answer

Answer to first part of the multi part question:

Density altitude is defines as pressure altitude corrected for non standard temperature variations.

Now converting 32000 ft into km we get 9.75 km. Since 1 km = 3280 ft.

We need to find the density , temperature and pressure of air at 32000 ft or 9.75 km

We know that without atmosphere there would be no life on Earth. Scientists have divided out atmosphere into four layers according to temperature: troposphere, stratosphere, mesosphere and thermosphere.

As per the question we need to find the weather conditions at 9.75km. We know that troposphere is the layer of Atmosphere extending upto 10 to 15 km.

Density: This layer is closest to the Earth's surface. It contains 75% of the atmosphere mass.

Temperature and pressure drops as we go higher up Troposphere. Typically the maximum air temperature occurs near the earth's surface and drops with an increasing height at an average of 6.5 C per 1000 m .The reason of such a decreasing gradient is that the earth is heated due to the sunlight hitting its surface.

Going by this, the temperature of air at 9.75 km = 58 oC

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