answer in detail please, thank you If you were to grow plants in a rectangular-s
ID: 2841543 • Letter: A
Question
answer in detail please, thank you
Explanation / Answer
a)perimeter =2(a+b)=10 so a+b=5ft
area=ab=a(5-a)
to maximize area d(ab)/da=0=>5-2a=0=>a=2.5 ft
so b=2.5 therefore area =2.5*2.5=6.25 ft^2
b initial velocity v0=20
at max height v=0=>dh/dt=0
-9.8t+20=0=>t=2.04s
so h at t=2.04 s ..put t=2.04s in H(t)
c) v=4*pi*r^3/3
=>dv/dt=4*pi*r^2*dr/dt
given dv/dt=2 ,, r=6=>dr/dt=2/(4*36*3.14)=0.0044
d) a+b+c=108
by arithmetic geometric mean theorem
(a+b+c)/3>=cube root (abc)=>abc<=36^3 equality holds for a=b=c.
so maximum volume =36*36*36
e) 1) for net sales put x=10 in s(t)
2) for rate of change dS/dt=-0.75x^2+0.46x+10=-60.4
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