Suppose parametric equations for the line segment between (8,2) and (5,?6) have
ID: 2839366 • Letter: S
Question
Suppose parametric equations for the line segment between (8,2) and (5,?6) have the form:
xy == a+btc+dt
If the parametric curve starts at (8,2) when t=0 and ends at (5,?6) at t=1 , then find a , b , c , and d .
a= ,
b= ,
c= ,
d= .
Explanation / Answer
when t = 0
x=a a = 8
y = c c = 2
when t = 1
x-8 = b b = -3
y-2 = d d = -8
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