-- Given an impedance of 5ohms 18degree with a voltage of 62V 69 degree, what is

Question

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Given an impedance of 5ohms 18degree with a voltage of 62V 69 degree, what is the phase of the current? Given an impedance with a current of 8A 13 degree and a voltage of 67V 40 degree, what is the angle of the impedance? Given an impedance of 4 ohms 13 degree with a current of 7A 23 degree, what is the magnitude of the voltage? Given an impedance with a current of 7A 4 degree and a voltage of 65V 13 degree, what is the magnitude of the impedance? Given an impedance of 5 ohms 85 degree with a voltage of 68V 6 degree, what is the magnitude of the current?

Explanation / Answer

8.
V=i*R
Phase of voltage=phase of current + phase of impedance
69=phase of current -18
phase of current =87 degree
9.
Phase of voltage=phase of current + angle of impedance
40=-13+angle of impedance
angle of impedance=53 degree

10.
Magnitude of V=I*Z=7*4=28 V
11.
magnitude of impedance=V/I=65/7
=9.286 ohm
12.
magnitude of current=V/Z=68/5
=13.6 A

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