categories, large and smail. We incubate these spores on spores that germinate b
ID: 280054 • Letter: C
Question
categories, large and smail. We incubate these spores on spores that germinate by producing a single and count the hypothesis is that spore size and oungrowth are independent of each other Based on the actual data shown below what is the expected number of large spores with multiple outgrowths igive answer to 1 decimal QUESTION 12 1 points Save Answer Consider a monohydrid cross, which is an Aa by Aa cross, where the expected outcome of genotype frequencies for the offspring is 1 to 2 to 1 using a Punnett square. You have observed 300 offspring with 80 AA, 163 Aa, and 35 aa genotypes. Please caleulate the chi-squared statistic for a test of the null hypothesis that the observed genotype counts in the offspring are equal to their expectation of I to 2 to (answer to 3 decimals) Use this handy.chi-quare caicadatoe QUESTION 13 2 points Save Answer Scottish researchers compared rates of depression between 94 undergraduates who regularly kept diaries and 41 students who did not. They found that people who kept diaries were more likely to have depression than those who did not. The researchers said, "We expected diary-keepers to have some benefit or be the same, but they were the worst o You are probably much better oft if you don't write anything at all This is an observational study, so it is not possible to ascribe that writing in a dary causel leads to depression (efect) Another explanation could be that peopke who are depressed are more likely to keep a diary. Their interpretation of the results was flawed because the researchers assumed an order of cause and effect. Their interpretation of the resuts was cormect because writing in a diary probsbly causes one to think too much on eirExplanation / Answer
Answer:
12) Based on the given information, monohybrid cross: Aa x Aa --> AA, Aa, Aa, aa
Expected genotype frequency = 1:2:1
Total number of offsprings = 300
Observed Number:
Expected Number:
Chi Square test:
Chi Square Table:
Degree of freedom = Number of categories - 1 = 3 - 1 = 2
P-value corresponding to Chi Square value of 7.167 with 2 degree of freedom is P-Value = 0.027778. The result is significant at p < 0.05
Since the P-value (0.0277) is less than the significance level (0.05), therefore, based on the experimental evidence the Null Hypothesis is rejected. Observed genotype counts in the offsprings are not equal to their expectation of 1 to 2 to 1
Genotype Observed Number (O) Expected Number (E) (O-E) (O-E)^2/E AA 80 75 5 0.333 Aa 165 150 15 1.500 aa 55 75 -20 5.333 Total 300 300 Chi Square (sum) 7.167Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.