Aa Question 1 [18 marks /18 minutes] In the pedigree to the right, allele a is a
ID: 279936 • Letter: A
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Aa Question 1 [18 marks /18 minutes] In the pedigree to the right, allele a is a rare, auto somal recessive, disease-causing allele. The genotypes of individuals I.1 and L.2 are given. II 2 4 1 IV 1 c) Using the original pedigree, calculate the probability that individual IV.1 wil show the disease if the a allele is dominant. Asume that penetrance of the disease genotype is complete. Explain your answer [6 marks] Based on your answer to part (c), calculate the probability that individual IV.1 will show the disease if the penetrance of the disease genotype is 50%. d) 2 marksExplanation / Answer
(1)
C.
In autosomal dominant inheritance, only one copy of a disease allele is required for an individual to be affected by the disease. With each pregnancy, there is a one in two (50%) chance the offspring will inherit the disease allele.
The probability of II-2, 3 are being affected is 50% or 1/2
Aa x AA= AA, AA, Aa, Aa (50% individuals will be affected)
Probability of III-1, III-2 being affected is ½ x ½ = ¼
Aa x AA = 50% are Aa
Probability that IV-1 is affected is = ¼ Aa x ¼ Aa= AA, Aa, Aa, aa = 1/16 x ¾ = 3/64
d)
If the penetrance is 50%, With each pregnancy, there is a one in four(%) chance the offspring will inherit the disease allele.
the Probability that IV-1 will show the disease is
1/16 x 1/16 x ½ x ¾ = 3/2048
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