heterozygous black guinea pigs (Bb) are crossed among themselves. what is the pr

Question

heterozygous black guinea pigs (Bb) are crossed among themselves. what is the probability of the first three offspring being alternatively black-white or white-black-white

Explanation / Answer

Black must be dominant in guinea pigs, since all the F1 offspring are black: BB x bb --> Bb and the black parent must be BB, rather than Bb, because there are no white, bb, offspring The F1 mating with each other (Bb x Bb) produces an F2 = BB:Bb:bb, in a ratio of 1:2:1, which is 3 blacks to 1 white. (The F2 individuals are produced by making all the possible combinations of gametes, 1 from each parent: B with B, B with b,then b with B, and b with b --> 1BB:2Bb:1bb) 2A. 1/3 of the black F2 pigs would be pure-bred dominant, that is, BB 2/3 of the black F2 pigs would be hybrid-heterozygous, that is, Bb 2B. all the white pigs are bb, none are hybrids (all the hybrids, Bb, are black, because black is dominant.

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