Problem 3 Figure 3 shows the biosynthesis pathway for the nutrient Z and a table

Question

Problem 3 Figure 3 shows the biosynthesis pathway for the nutrient Z and a table showing the results of a genetic dissection of that pathway. Each of the six mutants has a recessive mutation in a single gene. Refer to this figure as you consider the questions below. 13) How many of the mutants listed in the table the can convert X into V ?) all of them b) five c) four d) three e) fewer than three 14) Which of the following biochemical reactions can be catalyzed by mutant 1? d) None of the reactions listed e) All of the reactions listed 15) What is the substrate of the reaction catalyzed by the enzyme that is defective in mutant 5? a) V e) all of the above 16) Mutant 2 and mutant 5 were mated to create a diploid. This diploid is expected to be able to grow on which of the following media? a) minimal medium b) minimal medium plus V c) Both of the media listed above. d) Neither of the media listed above e) Not enough information is provided to determine the answer to this question. 17) Mutant 2 and mutant 6 were mated to create a diploid. This diploid is expected to be able to grow on which of the following media? a) minimal medium plus X b) minimal medium plus Y c) minimal medium d) All three of the media listed above. e) Not enough information is provided to determine the answer to this question. 18) A new mutant, mutant 7, was isolated. Mutant 7 has a recessive mutation in a single gene. Mutant 7 cannot grow on minimal medium or minimal medium plus W but can grow on minimal medium plus Z. On which other medium should mutant 7 be able to grow? a) minimal medium plus V b) minimal medium plus X c) minimal medium plus Y d) All three of the media listed above. e) None of the media listed above.

Explanation / Answer

As you provided in table the pathway is

X--->V--->Y--->W--->Z.

1) only mutant 6 is able to grow on minimal+X plate. so option E. fewer than three.

2) mutant 1 will grow on minimal+Z plate only. so option D. none of the reaction listed.

3) mutant 5 will grow on minimal+Y plate but not on minimal+V plate. so defective enzyme is which convert V--->Y. option A.

4) mutant 2 and 5 both are same. for this option D and E both are possible.

5) mutant 2 and 6 mated and this diploid cell will be able to grow on minimal+X plate. option A. but this diploid will not grow on minimal plate.

6) mutant 7 will be able to grow in minimal+Z plate. so option E is correct.

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