map distance question In squirrels, bushy tail (B) is dominant to smooth tail (b

Question

map distance question

In squirrels, bushy tail (B) is dominant to smooth tail (b), and gray coat (G) is dominant to brown coat (g). These two loci are linked. Pure-breeding gray, smooth-tailed squirrels were mated to pure-breeding brown, bushy-tailed squirrels. The F1 were testcrossed. Testcross progeny consisted of 278 gray, smooth-tailed, 22 gray, bushy-tailed, 306 brown, bushy- tailed, and 29 brown, smooth-tailed squirrels. Calculate the map distance between these two genes in centimorgans. Round your answer properly to 2 decimal digits. Type in only the numerical value for your map distance without indicating the units. Answer: 8.03

Explanation / Answer

Answer:

Based on the given information:

Pure Breeding gray, smooth-tailed squirrels (GGbb) x Pure Breeding brown, bushy-tailed squirrels (ggBB).

The parental gametes are: Gb, Gb, Gb, Gb and gB, gB, gB, gB

All F1 progeny will have the genotype: GgBb and Phenotype: Gray Coat, Bushy Tail

F1 were Test-Crossed: GgBb x ggbb

The parental gametes are: GB, Gb. gB, gb and gb, gb, gb, gb

Punnett Square:

Since, the recombination frequency is > 50%, these genes aren't linked or data is not consistent.

gb gb gb gb Phenotype GB GgBb GgBb GgBb GgBb Gray Coat, Bushy Tail Gb Ggbb Ggbb Ggbb Ggbb Gray Coat, Smooth Tail gB ggBb ggBb ggBb ggBb Brown Coat, Bushy Tail gb ggbb ggbb ggbb ggbb Brown Coat, Smooth Tail

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