Project A has a first cost of $3,500, annual operating and maintenance costs of
ID: 2724348 • Letter: P
Question
Project A has a first cost of $3,500, annual operating and maintenance costs of $1,900, annual savings of $2,300, and a salvage value of $1,800 at the end of its 5 year useful life.
Project B has a first cost of $6,000, annual operating and maintenance costs of $1,600, annual savings of $2,500, and a salvage value of $2,000 at the end of its 7 year useful life.
Using a MARR of 5%, answering the following questions:
What is the equivalent uniform annual worth (EUAW) of project A?
What is the equivalent uniform annual worth (EUAW) of project B?
Assuming a project will be replaced with an identical project at end of life, which project should be adopted by the company?
Explanation / Answer
Project A:nEt cash inflow = 2300-1900 = 400
Present value of cash inflow = (PVAF@5%,5 *Net cash inflow)+(PVF@5%,5 *Salvage)
=(4.32948* 400) + (.78353 * 1800)
= 1731.79+ 1410.35
= 3142.15
NPV = present value -II
= 3142.15 - 3500 = - 357.85
EUAW = NPV / PVAF@5%,5
= - 357.85 / 4.32948
= $ - 82.65
Project B:Present value = (PVAF@5%,7*Net cash inflow )+(PVF@5%,7 *Salvage)
= (5.78637 * 900 ) + (.71068 * 2000)
= 5207.73+ 1421.36
= 6629.09
NPV = 6629.09 - 6000 = 629.09
EUAW = 629.09 / 5.78637 = $ 108.72
C)Company shall select project B as it has positive NPV and EUAW
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