I marked the correct answer but I still didn’t understand why like I am not sure

Question

I marked the correct answer but I still didn’t understand why like I am not sure if my opinion right or not so I need your help for all questions listed in the first page and then use the second page as guide to help you for the first page! in Fgure 4 shows the inheritance of sickle ell anemia in a family and the results of Southern blot analysis of the ne for four family members (-1, 1-2, 11-1, and II-5). II-1 and III-2 were just born and neither their the p ) fourz sir DNA has been analyzed. The figure also shows a restriction map of Bt and p alleles and the location of three DNA probes (A, B and C). Use this information to help you answer the questions below 25) Which probe was used in the Southern blot analysis? er a) probe A b) probe B probe C et er 26) What is the probability that I1-1 will have only HbA in her red blood cells? a) 0 b) 1/4 c) 1/3 d) 2/3 27) If II-1 was analyzed by Southern blot using the same probe as that used on other members of the family, what is the probability that the result will be show two bands? a) 0 b) 1/4 d) 2/3 e) 1 28) How many individuals in the pedigree are certain to have at least some sickled red blood cells? a) more than six b) six C) five d) four e) less than four 29) How many individuals in the pedigree are certain to have only normal beta-globin protein in their red blood cells? a) more than six b) six c) five d) four less than four 30) If Il-2 is analyzed by Southerm blot using probe A, what is the probability that the result will be three bands? 0 d) 2/3 e) 1 c) 1/3

Explanation / Answer

25) probe C is used because it can detect 0.2kb (from the figure we can understand that this probe having complimentary binding for 0.2kb band) so that newly born III1 and III2 DNA can be analysed.

26) probability 1 (or 100%) because it is showing 0.2 kb band, if its having HbaA and HbaB it has show all three bands.

27) 1/3rd because as a probability 1/3 should have 2 bands, 1/3 shouls have 3 bands 1/3 should have 1 band

28) because probability of getting two bands is less than 4 offspring’s

29) because probability of getting one band is less than 4 offspring’s

30) zero because probe A is specific to 1.15 band only, if he wants to see three bands he has to use three probes A,B,C

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