Q1) If you performed a chi-square test on the number of genotypic classes produc
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Question
Q1) If you performed a chi-square test on the number of genotypic classes produced from the p+p- c+c- x p+p- c+c-, how many degrees of freedom would be relevant to the analysis (which row on the chi-square table would you refer to)?
Q2)
Select all that apply.
The chi-square values in the answers below are all from tests of dihybrid crosses based on the Mendel's principles of transmission genetics. Which of these chi-square values would allow you reject the hypothesis?
The Chi-square test = ? (O-E)2 . Chi-square value. x2 Table 2.4 The Chi-Square Table Probability (P) Value 0.50 0.46 1.39 2.37 3.36 0.30 1.07 2.41 0.10 2.17 4.61 0.001 10.83 13.82 0.95 0.90 0.70 0.15 0.71 142 0.20 0.016 1.64 0.10 0.35 0.71 1.15 0.58 1.06 1.61 7.82 9.49 11.07 9.21 11.35 13.28 15.09 4.88 5.99 7.78 18.47 3.00 6.06 7.29 9.24 10 03Explanation / Answer
Q1. This cross is resemebles with mendilian dihybrid cross. The possible number of categories(phenotypes) in these type of crosses is 4.
So, Degress of freedom = No. of categories - 1 => 4-1 = 3.
The answer is 3.
Q2. On the basis of its dihybrid crosses, the values at 0.05 and 3 DF values i.e. 7.82 is considered as p value to test the hypothesis.
So, the answer is 0.05.
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