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(2 points) A woman with blood type B, whose mother was type 0, has children with

ID: 268247 • Letter: #

Question

(2 points) A woman with blood type B, whose mother was type 0, has children with a man with type AB. What is the possible phenotypic ratio of their offspring? 3. 4. (1 point) A wild-type fruit fly (heterozygous for gray body color and normal wings) is mated with a homozygous black fly with vestigial wings. The offspring have the following phenotypic distribution: gray-normal -778 flies; black-vestigial -785 flies; black-normal -158 flies; gray- vestigial -162 flies. Determine the frequency of recombination. Frequency of recombination

Explanation / Answer

            Child can have (Ai), (Bi), (BA), (BB)

=320/1883=0.16