1. (2 pts) The equation for the frequency in a population is: p+q=1 2. (2 pts) T

Question

1. (2 pts) The equation for the frequency in a population is: p+q=1 2. (2 pts) The equation for the frequency in a population at HWE is: p2+2pq+q2=1 You decide to go out with your friends to First Friday. Whilst perusing all of the fancy abstract art, listening to the great music, watching people dance, and standing around just generally looking cool, you think back to your bio lab where you learned about populations at HWE. You realize that there are 100 people attending FF and decide to calculate the genotypic and phenotypic frequencies of the traits you see. Assuming that being a hipster is a purely genetic condition, you divide the group into two groups: Non-hipsters and hipsters. You count 30 hipsters. Assuming that hipster is the recessive allele (h) and non-hipster is the dominant allele (H), answer the following questions: a) What phenotypes correspond to the genotypes HH, Hh, hh? (2 pt total) HH: Hh: hh: b) Letting p be the frequency of the H allele and q be the frequency of the h allele, calculate the following (and show where your answers are coming from): (0.4 pts each) q= p= 2pq= q2= p2= c) Therefore, in the population, there are: (0.4 pts each) homozygous recessive individuals homozygous dominant individuals heterozygote individuals and: % of the alleles are H % of alleles are h

Explanation / Answer

a) HH and Hh are non hipsters and hh are hipsters. b) Under HWE f(hh) = q^2 = 30/100 = 0.3, so q = 0.55. As p+q = 1, p = 0.45 Therefore p^2 = 0.2 and 2pq = 0.5 c) In a population of 100 f(hh) = q^2 = 30; f (HH) = 20 and f(Hh) = 0.5 45% of the alleles are H and 55% are h.

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