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2. An annual plant has a population of 200 individuals in generation 4 and six g

ID: 261690 • Letter: 2

Question

2. An annual plant has a population of 200 individuals in generation 4 and six generations later, it has a population of 400 individuals.

a. What is the per capita rate of increase for this population?

b. What is the rate of increase for the population as a whole in the 10th generation?

c. If individuals are added to this population at a rate of 30% per year, what would be the total number of deaths expected in generation 10?

d. If the population has a carrying capacity of 1000 and a time lag of 4 generations between a given population density and the effects of density, by how much will this population overshoot its carrying capacity?

Explanation / Answer

a). Per capita increase in population is given by:

PR = G/N*100%

Where G= change in size of population, i.e= Final population- Intial population i.e 400-200

so G=200

N=200, as given in question, initial population at 4th generation.

putting these values in the formula:

PR = 200/200*100% =100%

Per capita increase in population= 100%

b). Increase in population a s a whole is given by= G/dT*100

Where G= Change is population =200(PREVIOUS CALCULATION)

dT= 10-4(AS WE ARE CALCULATING FOR A PERIOD BETWEEN 4TH GENERATION AND 10TH GENERATION)

=6

HENCE, Increase in polpulation in 10th generation= 200/6*100= 333%

c) Here since population is added at 30% per year

therefore at the end of 5th year population= 200+30%of 200=260

6th year=260+30%of 260=338, 7th year=338+30%0f 338=439.4=440(population is a whole number)

likewise10th year=967(calculating in the same way)

we are given population as 400 at the end of 10th year.

so, the deaths expected will be Total growth minus present population=967-400=567.