The Leu operon (prokaryotic gene regulation) There are two proteins that are inv
ID: 259915 • Letter: T
Question
The Leu operon (prokaryotic gene regulation) There are two proteins that are involved in the synthesis of the amino acid leucine. Leu1 is required for transport of the precursor oxopentanoate into the bacterial cell. Leu2 converts oxopentanoate into leucine. Their genes are both under the control of the same promoter. The operon is negatively regulated by a protein encoded by Leu3, under the control of a constitutive promoter. Transcription from the Leu operon is induced by the presence of oxopentanoate. Basal levels of transcription from this operon are very high. Repressed levels are undetectable.
You create five mutations (A- E) that are leucine auxotropbs. Assume the wild type version of each mutation encodes the functional version of each element. · . . . · teuA-is a frame shift early in the coding region of Leul. LeuB- is null mutation of Leu2. teve is a mutation in Leu3 that prevents it from binding to the inducer LeuD- mutates (destroys) the binding site (cis sequence) for the Leu3 protein suE-mutates (destroys) the promoter of the operon Predict whether or not we will see growth of bacterial colonies with the following genotypes under the following conditions. Enter YES (for growth) or NO (no growth) in the boxes below. Minimal medium containing: leucine Genotype oxopentanoate LeuDt, Leue- F' LeuAt, LeuB+, LeuC+, LeuD-, LeuE+Explanation / Answer
Genotype Oxopentanoate leucine LeuA+ LeuB+ LeuC+ LeuD+ LeuE+ Yes No LeuA- LeuB- LeuC+ LeuD+ LeuE+ No No LeuA+ LeuB+ LeuC- LeuD+ LeuE+ Yes Yes LeuA+ LeuB+ LeuC- LeuD- LeuE+ Yes Yes LeuA+ LeuB+ LeuC+ LeuD+ LeuE- No No LeuA- LeuB+ LeuC+ LeuD+ LeuE+/ F' LeuA+ LeuB- LeuC+ LeuD+ LeuE+ No No LeuA+ LeuB+ LeuC- LeuD+ LeuE+/ F' LeuA- LeuB- LeuC+ LeuD+ LeuE- Yes No LeuA+ LeuB+ LeuC- LeuD+ LeuE- / F' LeuA+ LeuB+ LeuC+ LeuD- LeuE+ Yes Yes
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