c) nucleus 4 d) none of them The yeast Schizosaccharomyces pombe normally divide

Question

c) nucleus 4 d) none of them The yeast Schizosaccharomyces pombe normally divides when it reaches a certain size, as shown in the wild type diagram below. (choose from the options below; note that not all options may be used and that some could be used more thun once) (A) Wild Type (C) Mutant 2 (D) Mutant 3 46. Which of the above diagrams corresponds to what a wee1 deficient cell? X 47 , which of the above diagrams corresponds to a cdc25 deficient cell? 48. Which one repreents a normal cell undergoing nitosis? 49. Which one represents a cell that got stuck in G22 O s0. Which diagram is representative of what a cell would look like if Chk1 were activated? O ? 599

Explanation / Answer

I believe the correct options to be

46) C) Mutant 2 as loss of wee1 will lead to premature division as this gene is responsible for determining the timepoint of entry of cell into mitosis.

47) B) mutant 1 as this gene is responsible for transition of cell from g1 to S phase so without the gene, the DNA would not be synthesised and seperated.

48) It is A) wild type as it is most normal of all the options.

49) D) mutant 3 as its genome is replicated but the cell keeps on growing without dividing.

50)B) mutant one as the cell would be arrested if chk1 becomes active whic is acticated in case of DNA damage response to give cell the time it needs to repair its DNA before replicating.

Feel free to leave a comment down below for any furhter query. Good rating would be appretiated if you find my answer helpful. Thank you.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.