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G O > OG UUU = phe UCU = ser UUC = phe UCC = ser UUA - leu UCA = ser UUG = leu U

ID: 259284 • Letter: G

Question

G O > OG UUU = phe UCU = ser UUC = phe UCC = ser UUA - leu UCA = ser UUG = leu UCG = ser CUU = leu CCU = pro CUC - leu CCC = pro CUA = leu CCA = pro CUG = leu CCG = pro AUU - ile ACU = thr AUC = ile ACC = thr AUA = ile ACA = thr AUG = met ACG = thr GUU = val GCU = ala GUC = val GCC = ala GUA = val GCA = ala GUG = val GCG = ala UAU = tyr UAC = tyr UAA = stop UAG = stop CAU = his CAC = his CAA = gin CAG = gin SAU = 0s AAC = asn AAA = lys AAG = lys GAU = asp GAC = asp GAA = glu GAG = glu UGU - cys UGC = cys UGA - stop UGG - tip CGU = arg CGC - arg CGA = arg CGG = arg AGU = ser AGC = ser AGA = arg AGG - arg GGU = gly GGC = gly GGA - gly GGG = gly

Explanation / Answer

5' NNN CUG UAU AGA GCC UGA UCG GCG GNN N 3'

1) frame 1 - X L Y R A & S A X

5' N NNC UGU AUA GAG CCU GAU CGG CGG NNN 3'

frame 2 - X C I E P D R R X

5' NN NCU GUA UAG AGC CUG AUC GGC GGN NN 3'

frame 3 - X V @ S L I G G

here @ and & are stop sequences so after that chain will terminate.

2) mRNA sequence is 5' N GCU GUG CGC GCN 3'

tRNA sequence is 3' N CGA CAC GCG CGN 5'

amino acid sequence will be- R H A R