G O > OG UUU = phe UCU = ser UUC = phe UCC = ser UUA - leu UCA = ser UUG = leu U
ID: 259284 • Letter: G
Question
G O > OG UUU = phe UCU = ser UUC = phe UCC = ser UUA - leu UCA = ser UUG = leu UCG = ser CUU = leu CCU = pro CUC - leu CCC = pro CUA = leu CCA = pro CUG = leu CCG = pro AUU - ile ACU = thr AUC = ile ACC = thr AUA = ile ACA = thr AUG = met ACG = thr GUU = val GCU = ala GUC = val GCC = ala GUA = val GCA = ala GUG = val GCG = ala UAU = tyr UAC = tyr UAA = stop UAG = stop CAU = his CAC = his CAA = gin CAG = gin SAU = 0s AAC = asn AAA = lys AAG = lys GAU = asp GAC = asp GAA = glu GAG = glu UGU - cys UGC = cys UGA - stop UGG - tip CGU = arg CGC - arg CGA = arg CGG = arg AGU = ser AGC = ser AGA = arg AGG - arg GGU = gly GGC = gly GGA - gly GGG = glyExplanation / Answer
5' NNN CUG UAU AGA GCC UGA UCG GCG GNN N 3'
1) frame 1 - X L Y R A & S A X
5' N NNC UGU AUA GAG CCU GAU CGG CGG NNN 3'
frame 2 - X C I E P D R R X
5' NN NCU GUA UAG AGC CUG AUC GGC GGN NN 3'
frame 3 - X V @ S L I G G
here @ and & are stop sequences so after that chain will terminate.
2) mRNA sequence is 5' N GCU GUG CGC GCN 3'
tRNA sequence is 3' N CGA CAC GCG CGN 5'
amino acid sequence will be- R H A R
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