The tool crib at a large manufacturing company is responsible for providing tool

Question

The tool crib at a large manufacturing company is responsible for providing tools to the factory workers on demand. The tool crib has a variable demand. Historically, its demand has ranged from 370370 to 520520 small tools per day with an average of 445445. Diane, the tool crib attendant, works eight hours a day, five days a week. Each order is for one small tool and each small tool takes Diane 11 minute to retrieve from the bins. What is the average waiting time, in minutes? (Round the final answer to the first decimal place.)

Explanation / Answer

Calculation of average waiting time in minutes :

                 Demand ranged from 370 to 520 small tools per day

                     Average small tool per day = 445

                   Tool crib working hours = 8 (480 minutes)

        Waiting time minutes = [445*(1 squared)]/{[2*(480min-(445*1))]}

                                            =[445]/[(2*35)]

                                            =445/70

                                            =6.35 minutes

        average waiting time in minutes = 6.35 minutes

note : the values given in the problem two times it is not correct because if we substitute that values we got negative answer (i,e. Negative minutes)

      so i have changed that values

                 370370         value is     370

                 520520          value is     520

                         11         i take it as   1

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