Loo 10 110 11.2 Determining Inheritance Recall that a Punnett square is a means

Question

Loo 10 110 11.2 Determining Inheritance Recall that a Punnett square is a means to determine the genetic parents are known. In a Punnett square, all possible types of sperm are ypes of eggs are lined up horizontally, or vice versa, so thar every within the square. Figure 11.3 shows bow t lined up vertically, and all possible possible oombination of gametes occurs to determine the genetic inberitance of offspring if the genotypes of both to construct a Punnett square when autosomal alleles are involved. Figure 11.3 Punnett square in a Punnett square, al ponsible sperm are displ ayed verticaly and all possible eggs nre oisp lsyed horzontaly or vice versn The genotypes of the oMspring on this cese, also the phenotypesi are in the squares Resuits of Cross ot widow's peak ospring Inheritance of Genetic Disorders Figure 11.4 can be used to leam the chances of a particular phenotype In Figure 11.4a, ¼ of the of1spring have the recessive phenotype ¾ of the offspring have the dominant phenotype- % chance % chance In Figure 11.4b, ½ of the offspring have the recessive or the dominant phenotype In all the following genetic problems, use letters to fill in the purentheses with the genorype of the parents I. a. With reference to Figure 1140, if a genetic disonder is recessive and both parents are ), what are the chances that an offspring will have the disorder? heterozygous) b. With reference to Figure 11.4a, if a genetic disorder is dominant and both parents are heterozygous ), what are the chances that an offspeing will have the disorder? 2. a. With reference to Figure 11.4b, if the parents are beterozygous (by homozygous recessive ), and the genetic disorder is recessive, what are the chances that the offspring will have the disorder? by homozygous recessive b. With reference to Figure 11.4b, if the parents are heterozygous( , and the genctic disorder is dominant, what are the chances that an offspring will have the disorder? 11-4 122 aboratory 11 Human Genetics

Explanation / Answer

In Figure 11.4a,¼ offspring have the phenotype= 25% chance

¾ offspring have the phenotype= 75% chance

Figure 11.4b, ½ offspring have the phenotype= 50% chance

Fill in the parentheses with the genotype of parents

1a. With reference to Figure 11.4a, if a genetic disorder is recessive and both parents are heterozygous (Aa), what are the chances that an offspring will have the disorder?1 in 4 (25%)

b. With reference to Figure 11.4a, if a genetic disorder is dominant and the parents are heterozygous (Aa), what are the chances that an offspring will have the disorder?3 out of 4 (75%)

2a. With reference to Figure 11.4b, if parents are heterozygous (Aa)by homozygous recessive (aa), and the genetic disorder is recessive, what are the chances that an offspring will have the disorder?50/50 (50%)

b. With reference to Figure 11.4b, if the parents are heterozygous (Aa) by homozygous recessive (aa), and the genetic disorder is dominant, what are the chances that an offspring will have the disorder?50/50 (50%)

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