Women who are carriers of an X-linked recessive trait typically do not exhibit t

Question

Women who are carriers of an X-linked recessive trait typically do not exhibit the trait themselves. However, there are some rare exceptions that occur because of X-chromosome inactivation, a in females mechanism Consider a woman who has a mutant allele of the blood clotting factor VII gene (Xa) and a healthy allele (X4). Because X-chromosome inactivation occurs at random, some fraction of her blood cells will carry an inactivated XA rendering them incapable of making functional clotting factor VII. Typically, because X-chromosome inactivation is random, her other blood cells carry an inactivated Xe and can make enough functional clotting factor VIII for the woman to be healthy. It is possible (though extremely rare) that, during development, every one of her precursor blood cells inactivated the wild-type x chromosome. As a result, this woman would have the blood clotting disorder. Two sisters are both heterozygous (XAX). One of these women has the blood clotting disorder. You would predict that her sister the blood clotting disorder. does not have also has

Explanation / Answer

lyonization

also has since both the sisters have same genotype, similar phenotype is expected. Although possibilities are there but they will be considered rare.

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