T. To control the cell cycle: a. the activity of Cdks stays the same throughout
ID: 257501 • Letter: T
Question
T. To control the cell cycle: a. the activity of Cdks stays the same throughout the cell cycle. b. cyclins fluctuate during the cell cycle. c. Cdks are active only when they are released from cyelins d. the anaphase-promoting complex stimulates DNA replication. e. M-Cdk inhibits mitosis. 48. In humans, assume that the allele for brown eyes is dominant and the allele for blue eyes is recessive. If two brown- eyed individuals have a child with blue eyes, that means: a. both parents are homozygous for brown eyes. b. both parents are heterozygous for eye color. c. there is a 1/4 chance that their second child will have brown eyes. d. there is a 1/2 chance that their second child will have blue eyes. 49. Which of the following represents the possible genotype(o) resuling from a cross between an individual homozygous for black hair (BB) and an individual homorygous for blonde hair (bb)? a. BB and Bb b. BB, Bb, and bb c. BB only d. Bb only c. bb only 50. If a coyple is planning on having two children, what is the probability that both will be male? a. 0 b. 1/4 c. 1/2 d. 3/4 51. Binding of a signal molecule to which type of receptor leads to a change in membrane poteatial? A. B. C. D. E. Tyrosine-kinase receptor G-protein-linked receptor Phosphorylated tyrosine-kinase dimer Ligand-gated ion channel Intracellular receptor 52. The activation of tyrosine-kinase receptors is characterized by A) Aggregation and phosphorylation B. IP, binding C. Calmodulin formation D. GTP hydrolysis E. Chanmel protein conformational changeExplanation / Answer
Answer:
47). C. Cdks are active only when they are released from cyclin.
The activity of these kinases rises and falls as the cell progresses through the cycle.
48). B. Both parents are heterozygous for eye color
Explanation:
Bb x Bb
B
B
B
BB (brown)
Bb (brown)
b
Bb (brown)
bb (blue)
49). D. Bb only
BB x bb--Parents
Bb---Offspring
50). B. ¼
Explanation: Probability of male and female is equalt, i.e., ½
Male, male = ½ * ½ = ¼
51) d. Ligand-gated ion channel
52). A. Aggregation and phosphorylation
B
B
B
BB (brown)
Bb (brown)
b
Bb (brown)
bb (blue)
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