1. Species I is diploid (2n-4) with chromosomes AABB; related species II is dipl

Question

1. Species I is diploid (2n-4) with chromosomes AABB; related species II is diploid (2n-6) with chromosomes MMNNOO. Give the ploidy (i.e. 2n, 3n, 2n-1, etc.) and the chromosomes (AABB, MMNNOO, etc.) that would be found in individuals with the following chromosome mutations. If a chromosome mutation only involves one or two types of chromosomes, use the first chromosome pair (M), then the second (N), etc. (0.25 pts. each; 2 pts. total). Mutation Ploidy Chromosomes present Autotetraploidy in species I Allotetrapoidy of species I and II Monosomy of species I Trisomy in species II Tetrasomy in species I Nullisomy in species II 2 Double trisomy in species II Triploidy in species

Explanation / Answer

1) autotetraploidy of species I = 4n = 8 chromosome. (AAAABBBB).

2) allotetraploidy of species I and II = for (species I, n=2, and for species II, n=3. cross b/w them then 2n = 5) so allotertaploidy of sp I and II is = 4n = 10 chromosome.

3) monosomy of sp I = 2n-1 = 3 chromosome.

4) trisomy of sp II = 2n+1 = 7.

5) tetrasomy in sp II = 2n +2 = 8 chromosome.

6) nullisomy of sp II = 2n-1 = 5 chromosome.

7) double trisomy in sp II = 2n +1+1 = 8 chromosome.

8) triploidy in sp I = 3n = 6 chromosome.

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.