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Below is a list of steps of eukaryotic pre-mRNA processing. Please in the CORREC

ID: 256873 • Letter: B

Question

Below is a list of steps of eukaryotic pre-mRNA processing. Please in the CORRECT sequential order stepanition and binding the 3 AAUAAA sequence by specific protein factors Cleavago ar hthe poly(A)site to the cytoplasm 5. Addition of the poly(A) tail A) 2, 3, 4, 5,1 B)3, 1, 2, 5,4 C) 4, 2, 3, 1,5 D) 5, 4, 1, 3, 2 E) 1, 3, 5, 4,1 20. Suppose an organism ingests a drug that disassembles its spliceosomes, rendering them nonfunctional. Which of the following would be seen MOST immediately in this organism? A) Introns would not be removed from the pre-mRNA. B) tRNA bases would no longer be modified into rare bases. C) All translation would stop D) mRNA would not be able to bind the 5 cap. E) rRNA would no longer be appropriately processed. 21. Anticodons are found in molecules. A) miRNA B) rRNA C) tRNA D) snRNA E) mRNA 22. Which of the following is observed in prokaryotes but not in eukaryotes? A) An mRNA can be translated by only one ribosome at a time in prokaryotes. B) UGG is an example of a stop codon only found in prokaryotes. C) Translation does not require any protein factors in prokaryotes. D) The 5 end of a prokaryotic mRNA can be translated while the 3 end is still being tra E) In prokaryotes, ribosomes move along an mRNA in the 3 to 5 direction. 23. The amino acid sequence of a polypeptide is referred to as the sequenc polypeptide B) secondary D) quatemary A) primary C) tertiary 24. There aredifferent codons, which encode 20 amino acids and 3 stop A) 16 B) 20 C) 23 D) 61 E) 64

Explanation / Answer

Answer 19. The correct option is B.

Answer 20. The correct option is A. If spliceosomes are non functional then it will not remove the introns from pre-mRNA.

Answer 21. Anticodon is a sequence of three nucleotides forming a unit of genetic code and it is found in a tRNA.

Answer 22. The correct option is D. In prokaryotes it is a common phenomenon.

Answer 23. The correct option is A.

Answer 24. The correct option is E. 61 for amino acids and 3 for stop codons.

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