Its in an inability to form blood clots. Albinism is an autosomal recessive trai

Question

Its in an inability to form blood clots. Albinism is an autosomal recessive trait that results in a lack of and eye pigmentation. Cathy is a normal-pigmen whose father was albino and hemophiliac. Bill is a normal-pigmented, h whose mother was albino with normal blood clotting. a) If Bill and Cathy have children, what is the probability that they will have a hemophiliac, skin, hair, ted woman with normal blood clotting emophiliac man normal-pigmented son? b) What is the probability that their first two children will be a normal-blood clotting, normal-pigmented son and a hemophiliac, albino daughter? o) What is the probability that their first two children will be either two albino, hemophiliac sons or two normal-pigmented, normal-blood clotting sons

Explanation / Answer

Lets say autosomal recessive albinism trait is denoted by recessive allele a and dominant allele as A.

Haemophilic recessive allele as x and dominant allele as X.

Cathy is a normal pigmented woman with normal blood clotting but her father was albino and haemophilic so cathy must be the carrer of the recessive genes. Her genotype will be AaXx.

Bill is normal pigmented hemophilic with her mother being albino, he will carry the recessive albino gene and recessive x linked hemophilic gene. His genotype will be AaxY.

A cross between Cathy and Bill

AAXx

(NN)

AAXY

(NN)

AaXx

(NN)

AaXY

(NN)

AAxx

(NH)

AAxY

(NH)

Aaxx

(NH)

AaxY

(NH)

AaXx

(NN)

AaXY

(NN)

aaXx

(AN)

aaXY

(AN)

Aaxx

(NH)

AaxY

(NH)

aaxx

(AH)

aaxY

(AH)

a) The probability of having normal pigmented haemophilic son(NH) is = 3/16= 0.18

b) The probability that their 1st two child will be normal blood clotting normal pigmented son(NN) (3/16) and hemophilic albino daughter (AH= 1/16) = 3/16 X 1/16 = .0112

c) The probability of having the 1st two child as two albino haemophilic sons is (AH)=1/16X1/16= .0039

The probability of having the 1st two children to be normal pigmented normal blood clotting son (NN)= 3/16X3/16 =.0351

comined probability of having either of them =.0039X.0351= .0001

Ax AY ax aY AX

AAXx

(NN)

AAXY

(NN)

AaXx

(NN)

AaXY

(NN)

Ax

AAxx

(NH)

AAxY

(NH)

Aaxx

(NH)

AaxY

(NH)

aX

AaXx

(NN)

AaXY

(NN)

aaXx

(AN)

aaXY

(AN)

ax

Aaxx

(NH)

AaxY

(NH)

aaxx

(AH)

aaxY

(AH)

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