Intron #21 in the CFTR gene (cystic fibrosis) is 25 nucleotides long. Suppose th

Question

Intron #21 in the CFTR gene (cystic fibrosis) is 25 nucleotides long. Suppose that this intron fails to get removed from the mRNA during mRNA processing. Predict the kind of mutation that this would introduce to the CFTR protein by circling your answer from the list below and explain your reasoning. [Hint: Recall how many nucleotides make one codon for one amino acid. Relate it to the intron size to identify the type of mutation] 2) (2 pts.) Missense Mutation . Nonsense Mutation Silent Mutation . Frameshift Mutation This would not change the CFTR protein Explanation

Explanation / Answer

2. Ans- Frameshift mutation
Explanation:
According to the above question, there are 25 nucleotides that add to the mRNA which will be translated.Therefore,
number of codons is 25 nucleotides= 8 1/3 codons

So, 8 additional amino acids are inserted. Therefore, it is a frameshift mutation and the protein will likely be nonfunctional and different from normal.

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