Introducing the F plasmid into the cells with Mutation 5 does not appear to have

Question

Introducing the F plasmid into the cells with Mutation 5 does not appear to have any effect on the mutant phenotype (it exhibits constitutive expression) The F' plasmid appears to "rescue" Mutation 6 by returning that cell line to wild-type expression. There are two possible mutations that could lead to constitutive expression - a loss of function mutation of the operator (OF) or the repressor protein (lact). To determine the effect of introducing a wild-type F' plasmid into a bacterial cell with each of these mutations, you draw out the two possible scenarios. F cap+ P+ o+ Z+ cap+ P+ O+ Z+ capt P+ Oc Z+ For each of the possible partial diploids, determine whether expression of the lac operon will be inducible (wild type) or constitutive (mutant). Then use this information to identify the mutations In Mutation 5 and Mutation 6 Select the two correct answers. F / is inducible Mutation 6 is a lact mutation. F / is constitutive Mutation 5 is a lach mutation FO/OP is inducible. Mutation 6 is a lacOc mutation. F O+/Oc is constitutive Mutation 5 is a laco mutation.

Explanation / Answer

The correct answers are F'I+/I- is inducible and mutation 6 is a lacI- mutation and F' O+/Oc is constitutive and mutation 5 is a lack mutation. As mutation 5 is giving the constitutive phenotype the operator must be mutated so that repressor is not able to bind operator and the expression is constitutive. And mutation 6 make cell return to wild type expression because the lacI- mutation  

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