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The ABO blood-typing system has been used to settle cases of disputed paternity

ID: 253569 • Letter: T

Question

The ABO blood-typing system has been used to settle cases of disputed paternity ppose, as a geneticist, you must testify during a case in which the mother has type A blood, the child has type O blood, and the alleged father has type B blood Suppose, as a geneticist, you must case in How would you respond to the following statements? a. Attorney of the alleged father: "The mother has type A blood, so the child's blood type must have come from the father. Because my client has type B blood, he could not have fathered the child." b. Mother's attorney: "Further tests prove the man is heterozygous, so he must be the father." How would you respond if the alleged father was type AB? c. 9. Extra Credit: Fur color in mice is governed by genes concerned with producing and distributing melanin. At one locus, a dominant allele (B) specifies dark brown and a recessive allele (b) specifies light brown, or tan. At another locus, a dominant allele (E) permits melanin production and a recessive allele (e) shuts it down and results in albinism or white mice. If you cross two heterozygous brown mice with the genotype BbEe what would the phenotype and genotype ratios would you expect?

Explanation / Answer

Answer:

1)

In this case, the mother' blood group is A and she has the genotype IAIO

Father's blood group is B and he has the genotype IBIO

The maternal gametes will be: IA, IO and paternal gametes will be IB, IO

The punnett square for this cross can be represented as:

So one of the possible genotypes of the offspring is IOIO that corresponds to O blood group. Therefore a child whose mather has A blood group and father has B blood group, can have O blood group (genotype IOIO).

2)


Based on the given information:

Color:

Melanin Production:

The genetic cross is:
Two heterozygou brown mice are crossed BbEe x BbEe. This cross can be represented using a punnett square as below:

The parental gametes are: BE, Be, bE, be and BE, Be, bE, be

Expected Genotype Ratio: 1:2:2:4:1:2:1:2:1

Expected Phenotypic Ratio:

Therefore, Phenotypic ratio is: 9:3:3:1

IA IO IB IAIB IBIO IO IAIO IOIO