please explain stepwise with some base 21.77 Consider the following segment of m

Question

please explain stepwise with some base

21.77 Consider the following segment of mRNA produced by the normal order of DNA nucleotides 5 ACA UCA CGG GUA 3 a. What is the amino acid order produced from this mRNA? b. What is the amino acid order if a point mutation changes UCA to ACA? C. What is the amino acid order if a point mutation changes CGG to GGG? d What happens to protein synthesis if a point mutation changes UCA to UAA? e. What is the amino acid order if an insertion mutation adds a G to the beginning of the mRNA segment? . What is the amino acid order if a deletion mutation removes the A at the beginning of the mRNA segment?

Explanation / Answer

a) Amino acid order- 5'-Threonine-Serine-Arginine-Valine-3'

b) The amino acid order does not change as both UCA and ACA codes for same amino acid threonine.

c) GGG codes for glycine- so the order will be- 5'-Threonine-Serine-Glycine-Valine-3'

d) UAA is a stop codon so the protein synthesis will stop after coding Threonine.

e) If insertion of G at the beginning of mRNA occurs the sequence will become- 5' GAC AUC ACG GGU A- 3'

and the amino acid order will be 5'-Aspartate-Isoleucine-Threonine-Glycine-3'

f) If deletion mutation removes A at the beginning of mRNA, the mRNA sequence becomes

5'-CAU CAC GGG UA-3'. And the amino acid order will be 5'-Histidine-Histidine-Glycine-3'

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