8. A satellite in outer space is moving at a constant velocity of 21.5 m/s in th

Question

8. A satellite in outer space is moving at a constant velocity of 21.5 m/s in the +y direction when one of its onboard thruster turns on, causing an acceleration of 0.270 m/s2 in the +x direction. The acceleration lasts for 49.0 s, at which point the thruster turns off.

(a) What is the magnitude of the satellite's velocity when the thruster turns off?

________ m/s

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.

_______  ° counterclockwise from the +x-axis

Explanation / Answer

the satellite moves with velocity 21.5 m/s in y- direction

it has acceleration of 0.270 m/s2 for 49.0 s

so the velocity in +x- direction will be calculated using the equation of linear motion

v = u + at

v = 0 + (0.27)*49

v = 13.23 m/s in +x-direction

magnitude of satellite's velocity = sqrt(Vx^2 + Vy^2)

V = sqrt (21.5^2 + 13.23^2)

V = 25.24 m/s

b) direction of satellite's velocity

theta = tan^-1(21.5/13.23) = 58.4 °

Answers

a) magnitude of satellite's velcoity = 25.24 m/s

b) 58.4 ° counterclockwise from the x- axis

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