O 1/29/2016 11:55 PM A 45.1/100 Gradebook Print Calculator Periodic Table Questi
ID: 251881 • Letter: O
Question
O 1/29/2016 11:55 PM A 45.1/100 Gradebook Print Calculator Periodic Table Question 12 of 12 Map pling A 15.41-mC charge is placed 35.65 cm to the left of a 60.73-mC charge, as shown in the figure, and both charges are held stationary. A particle with a charge of -2.551 uC and a mass of 20.81 g (depicted as a blue sphere) is placed at rest at a distance 32.09 cm above the right-most charge. If the particle were to be released from rest, it would follow some complicated path around the two stationary charges Calculating the exact path of the particle would be a challenging problem, but even without performing such a calculation it is possible to make some definite predictions about the future motion of the particle. If the path of the particle were to pass through the gray point labeled A what would be its speed vA at that point? -2.551 AC Number 32.09 cm +15.41 mC +60.73 mc K- 10.70 cm 35.65 cm O Previous ® Give Up & View Solution Check Answer Next Ext HintExplanation / Answer
Potential energy at its original position:
E0 = -k*4.551x10^-6*18.41x10^-3/sqrt(0.3315^2+0.2984^2)-k64.23x10^-3*4.551x10^-6/0.2984
= -8.99*10^9*4.551*10^-9 (18.41/0.446+64.23/0.2984)
.91 (256.53)
=-10494.5 J
EA = -k*4.551x10^-6*18.41x10^-3/0.09945 -k64.23x10^-3*4.551x10^-6/(0.3315-0.09945)
= -40.91 (18.41/0.09945+64.23/0.2984)
.91 (461.91)
=-18896.2 J
deltaE = E1-EA = 8402.3 J =1/2 mV^2
V = sqrt(2*8402.3/0.04131)
V = 451.0 m/s
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