Energy from the Sun arrives at the top of the Earth\\\'s atmosphere with an inte
ID: 251129 • Letter: E
Question
Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.36 kW / m2. How long does it take for 3.55 × 109 J to arrive on an area of 4.75 m2?_____s
The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.23 m. She sets the pendulum swinging, and her collaborators carefully count 101 complete cycles of oscillation during 206 s. What is the result?______m/s2
Explanation / Answer
Here ,
intensity , I = 1.36 kW/m^2
energy , E = 3.55 *10^9 J
area , A = 4.75 m^2
let the time taken is t
energy = intensity * area * time
3.55 * 10^9 = 4.75 * 1.36 *10^3 * t
solving for t
t = 5.495 *10^5 s
the time taken is 5.495 *10^5 s
---------------------
length of pendulum , L = 1.23 m
let the acceleration due to gravity is g
time period = total time/number of cycles
206/101 = 2*pi*sqrt(L/g)
206/101 = 2 * pi * sqrt(1.23/g)
solving for g
g = 11.7 m/s^2
the acceleration due to gravity is 11.7 m/s^2
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