The function y(x,t) = (.150 m)cos(pi x - 15 pi t) where x is in meters, and t is

Question

The function y(x,t) = (.150 m)cos(pi x - 15 pi t) where x is in meters, and t is in seconds, describes a transverse wave on a taut string. What is the transverse velocity of a point on the string at an instant in time when y = + 0.120 m What is the maximum transverse velocity a point on the string can have What is the average transverse velocity of a point on the string averaged over an integer number of wave periods What is the wave speed How does the wave speed compare with the value you calculated in b Is there any meaningful comparison to be made between your answers to b) and e)

Explanation / Answer

A) transverse velocity is v = dy/dt = (0.15*15*pi)*sin(pi*x - 15*pi*t)

v = (0.15*15*pi)*sin(pi*x - 15*pi*t)

B) maximum tranverse velocity is Vmax = A*w = (0.15*15*pi) = 0.15*15*3.142 = 7.0695 m/s

C) v = lamda/T = (2*pi/k)/T

where T is the wave period

D) wavespeed is v = w/k = (15*pi)(pi) = 15 m/s

E) wave speed is larger when compared with velocity of a point on the string

it is not the meaningful comparision between the answers to b) and c)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.