The amount of water in reservoirs is often measured in acre-ft. One acre-ft is a

Question

The amount of water in reservoirs is often measured in acre-ft. One acre-ft is a volume that covers an area of one acre to a depth of one foot. An acre is 43,560 ft^2. Find the volume in SI units of a reservoir containing 35.0 acre-ft of water. Kinetic energy KE has dimensions kg middot m^2/s^2. It can be written in terms of the momentum p and mass m as Determine the proper units for momentum using dimensional analysis. Force has the SI units kg middot m/s^2. Given the units of force, write a simple equation relating a constant force F exerted on an object, an interval of time t during which the force is applied, and the resulting momentum of the object, p. (Submit a file v/ith a maximum size of 1 MB.) Choose File] No fiie chosen

Explanation / Answer

here,

1)

one acre = 43560 ft^2

35 acre-ft = 35 * 43560 ft^3

35 acre-ft = 35 * 43560 * 0.3048^3 m^3

35 acre-ft = 43171.86 m^3

the volume in SI unit is equals to 43171.86 m^3

2)

dimensions of KE = kg.m^2/s^2

KE = p^2 / 2m

p = sqrt(KE * 2 * m )

therefore ,

p = sqrt(kg * kg.m^2/s^2
)

p = kg.m/s

the dimensions of momentum is kg.m/s

(b)

force = kg.m^2/s

force = impulse /time

force = change in momentum /time

f = ( pf - pi) / t

t is the time interval

(3)

r = 5.4 m

theta = 12 degree

x coordinate = r * cos(theta)

x = 5.4 * cos(12)

x = 5.28 m

y coordinate = r * sin(theta)

y = 5.4 * sin(12)

y = 1.12 m

(4)

r = 2.7 m

theta = 33 degree

x coordinate = r * cos(theta)

x = 2.7 * cos(33)

x = 2.26 m

y coordinate = r * sin(theta)

y = 2.7 * sin(33)

y = 1.47 m

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