solve -12 points SerPSE9 18.P.008.W My Notes Ask Your Teache Two ldentical louds

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-12 points SerPSE9 18.P.008.W My Notes Ask Your Teache Two ldentical loudspeakers are placed on a wall 3.00 m apart. A listener stands 5.00 m from the wall directly in front of one of the speakers. A single oscillator is driving the speakers at a frequency of 300 Hz. (a) what is the phase difference in radlans between the waves from the speakers when they reach the observer? (Your answer should be between o and 2t.) rad (b) What is the fraquency closest to 300 H2 to which the oscillator may be adjusted auch that the observer hears minimal sound? Hz Need Helo? Read ease

Explanation / Answer

1 soln

P O ................. 3 m ................. O Q



................................* A Person

path difference ( ) between 2 waves reaching A
= PA - QA = 5 - 3 = 2m
phase difference = = (2 / )
= (2 *f/ v) *2 --------- (1)
--------------------------------------...
I (resultant) = I1 + I2 + 2[I1*I2]^1/2 * cos ()
I1=I2 = identical waves
I = 2I1 [1 + cos ()]
I = 0 for destructive
cos = - 1 = cos (lowest), cos 3 ..........
phase difference = radians

= (2 *f/ v) *2=
(2 f) *2= v
frequency = lowest = f = v/4 = 343/4= 85.75 Hz

2 soln

= 0.005/8= 0.000625kg/m
T= 6*9.8= 58.8N
v=(T/) = (58.8/0.000625)=306.72m/s
f=v/2L = 306.72/(2*5)= 30.672= 30.672[Hz] approx

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