The total cross-sectional area of the load-bearing calcified portion of the two

Question

The total cross-sectional area of the load-bearing calcified portion of the two forearm bones (radius and ulna) is approximately 2.40 cm2 . During a car crash, the forearm is slammed, hand first, into the dashboard. The arm comes to rest from an initial speed of 80.0 km/h in a time of 5.00 ms. If the arm has an effective mass of 3.00 kg and bone material can withstand a maximum compressional stress of 16.0 × 107 Pa, is the arm likely to withstand the crash?

PLEASE HELP AND SHOW ALL STEPS SO I CAN TACKLE PROBLEMS LIKE THIS IN THE FUTURE THANK YOU!

Explanation / Answer

average force on arm will = avg rate of change of momentum

that is = 3*80*(5/18) - 0 / 0.005 = 13,333.33 N

area in m2 = 2.40 x 10-4 m2

stress = 13,333.33/2.4* 10-4 = 5,555,555.55 pa = 55.56 Mpa

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.