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Safari File Edit View History Bookmarks Window Help 16% D Tue Jan 12 2:07 PM a :E session masteringphysics.com Large El PHYS 112 General Physics Sp 16 RedBull Help Close Ch Resources Chapter 20 Homework Problem 20.9 previous 5 of 13 l next EPI 480 Problem 20.9 Part A Two 1.0 kg masses are 4.0 m apart on a What is the magnitude of the electric force on one of the masses? frictionless table. Each has 1.0AC of charge. Fall 15 syllabu Express your answer using two significant figures Mor Josh/Trial Subm My Answers Give Up Part B What is the initial acceleration of each mass if they are released and allowed to move? Express your answer using two significant figures m/s2 Subm My Answers Give Up 758 answers

Explanation / Answer

PART ONE

Coulomb's Law to solve for force between masses.

F = k * { [q1q2] / r^2 }

F = Force between charges
k = Coulomb's constant
q1 = Charge one
q2 = Charge two
r = Distance

Data in SI units (convert mC to C):

k = 8.987E+9 N-m^2/C^2
q1 = 1.0E-6 C
q2 = 1.0E-6 C
r = 4.0 m

Solve for force

F = (8.987E+9 N-m^2/C^2) * { [ (1.0E-6 C) * (1.0E-6 C) ] / (4.0 m)^2 }
F = (8.987E+9 N-m^2/C^2) * { [ 1.0E-12 C^2 ] / (16.0 m^2) }
F = (8.987E+9 N-m^2/C^2) * { 6.25E-14 C^2/m^2 }
F = 5.62E-4 N

PART TWO

Newton's 2nd Law to solve for initial acceleration, equation solved for accelertaion

F = m * a
a = F/m

F = Force applied
m = Mass of object
a = Acceleration

Data in SI units:

F = 5.62*10^-4 N
m = 1.0 kg

a = (5.62*10^-4 N) / (1.0 kg)
a = 5.62*10^-4 m/s^2

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