-An 8 g bullet is fired horizontally into a 9 kg block of wood on a air table an

Question

-An 8 g bullet is fired horizontally into a 9 kg block of wood on a air table and is embedded in it . After the collision, the block and the bullet slide along a frictionless surface together with a speed of 10 cm/s. What is the initial speed of the bullet?

-A bullet of mass m, moving at speed v1, goes through a motionless wooden blockand exits with speed v2. After the collision, the block, which has mass mb, is moving.(All answers should be in variables.)

a. What is the final speed, vb, of the block?

b. How much energy was lost to the bullet?

Explanation / Answer

Problem 1

conserving momentum o the systemg

let V be intial velocity of bullet

there fore

0.008* V = (9+0.008)*10

V = 11.260 cm/sec

Problem 2

a) conserving momentum

m V1 = mV2 + mbvb

Vb = m(V1-V2) /Mb

b) energy lost = initial - final kinetic energy

energy lost = 0.5 m ( V1^2 -V2^2)

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