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PART 1 PART 2 Use the cost information for each option listed in problem 1. You

ID: 2482656 • Letter: P

Question

PART 1

PART 2

Use the cost information for each option listed in problem 1. You also estimate that the average daily revenues are 20k./day for each day the crane is operating. For the purpose of this analysis assume that the crane will operate 150 days/yr for the next5 years. CORPORATE TAX RATE = 4% MARRat = 10% and use MACRS-GDS 5 yr. property classification for the for depreciation allowance. Assume that the existing crane has been fully depreciated prior to this analysis and ignore inflation effects.

Find:

A) After tax cash flows for each option

B) after tax present worth of each option and your choice for crane services.

next 5 years if you keep existing crane you immediately invest 250k for repairs to ensure 5 year use with 0$ salvage value market value 200k if you purchase new crane assume that you can sell and recover the full market value (200k) MARR 10% items opt 1: keep existing opt 2 purchase new initial cost 250,000 (repair) 750,000 o&m per year 7,500 5,000 daily operation expesnes 600.day 300/day salvage value eoy5 0 250,000 find a) number of crane operating days/year required to be indifferent between choosing opt 1 or opt 2 b) best option if u are predicting a need for at least 150 crane operating days per year over the next five years

Explanation / Answer

EXISTING NEW Year Details 0 Initial cost -250000 -250000 750000 750000 1 O&M 7500 90000 97500 5000 45000 50000 2 7500 90000 97500 5000 45000 50000 3 7500 90000 97500 5000 45000 50000 4 7500 90000 97500 5000 45000 50000 5 7500 90000 97500 5000 45000 50000 Salvage -250000 -250000 a) To be indifferent PVs of costs less salvage value should be same for both the options 250000+226500/1.1*^1+(7500*3.79079)+(600*x)*3.79079=750000+(5000*3.79079)+(300*x)*3.79079-(250000/1.1^5) Solving for x, we get the no.of days in a year to be 276.725 ie. 277 days b. Initial cost 250000 Initial cost 750000 PV of annual costs 97500*3.79079 369602 PV of annual costs 189540 (PVOA 10%,5 yrs. 97500) 50000*3.79079 PV of costs 619602 Less: PV of Salvage 250000/1.1^5 155230 PV of costs 784309 b) So, best option if we are predicting a need for at least 150 crane operating days per year over the next five years will be Repairing the EXISTING machine as its PV of costs 619602 < 784309 PART-2 EXISTING O& M costs are contractual fixed payments-assumed to be not affected per-day calculations MACRS Year Details Revenues Taxable Income Tax @4% IAT Add: Dpn.Tax Shield @ Macrs On 250000 After tax Cash flow PV F @ 10% After tax Present Worth @ 10% 0 Initial cost -250000 -250000 1 -250000 20 1 O&M 7500 90000 3000000 2902500 116100 2786400 50000 2836400 0.90909 2578543 32 2 7500 90000 3000000 2902500 116100 2786400 80000 2866400 0.82645 2368936 19.2 3 7500 90000 3000000 2902500 116100 2786400 48000 2834400 0.75131 2129513 11.52 4 7500 90000 3000000 2902500 116100 2786400 28800 2815200 0.68301 1922810 11.52 5 7500 90000 3000000 2902500 116100 2786400 28800 2815200 0.62092 1748014 5.76 10497816 100 NEW MACRS Year Details Revenues Taxable Income Tax @4% IAT Add: Dpn.Tax Shield @ Macrs On 750000 After tax Cash flow PV F @ 10% After tax Present Worth @ 10% 0 Initial cost -750000 -750000 1 -750000 20 1 O&M 5000 45000 3000000 2950000 118000 2832000 150000 2982000 0.90909 2710906 32 2 5000 45000 3000000 2950000 118000 2832000 240000 3072000 0.82645 2538854 19.2 3 5000 45000 3000000 2950000 118000 2832000 144000 2976000 0.75131 2235899 11.52 4 5000 45000 3000000 2950000 118000 2832000 86400 2918400 0.68301 1993296 11.52 5 5000 45000 3000000 2950000 118000 2832000 86400 2918400 0.62092 1812093 5.76 Salvage 250000 10000 240000 240000 0.62092 149021 100 10690069 As NPW is more, NEW crane services are recommended.