The GCP 4000 is similar to the GCP 3000 but requires completely new components.
ID: 2437548 • Letter: T
Question
The GCP 4000 is similar to the GCP 3000 but requires completely new components. Components A, B, and C are assembled in house, but D, E, and F are sourced from vendors with the following shipment times:
Line Balancing Information: The GCP 4000 is produced with the following steps:
Additional Information:
• A backorder costs Vasquez Industries $10 per item.
• Storing an item at the warehouse costs $2 per item per month.
• Based on training and severance, there is a one-time $2000 cost for hiring a worker and a $3000 for firing a worker due to production.
Given the product structure, what is your ordering strategy for vendor-procured items?
Determine how the jobs should be scheduled in order to minimize the total makespan. Include an appropriate chart indicating the optimal schedule.
Using line balancing, how you recommend structuring work? How many assembly lines are needed based on a 36 hour workweek and 4 week month.?
End Item A(2) F1) One Weelk Two Weeks Two Weeks F(2) One Week E(2) One Week Figure 1: Question 1 Product Structure DiagramExplanation / Answer
According to the question, Components F, & E will take the shortest time to be delivered, that is one week, however, Component D takes the longest time, that is, 2 weeks. So, Component D should be ordered first with a time gap of 3 weeks from production, and Components F, and E should be ordered next with a time gap of 2 weeks. Component A should be produced 2 week before production, and C, and E should be produced 1 week before production.
The job should be scheduled in the following manner -
1, and 3 --> 2, and 4 --> 5 --> 6.
(Job 1 & 3 have no predecessor activities. Job 2 requires Job 3 & Job 1. Job 4 requires 3, 5 requires 4, and 6 requires 5)
For calculating required amount of assembly lines, we first need to calculate cycle time.
Cycle time = Production Time Per Day / Output
= 5/.5 = 10
No. of assembly lines needed = Total Task Time/Cycle Time
=(2+5+7+4+3+8)/10 = 3.
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