20f 5,0 complete) ? Hw Score: 0%, 0 of 5 pts 11.6.2 Question Help * Adrug s orde

Question

20f 5,0 complete) ? Hw Score: 0%, 0 of 5 pts 11.6.2 Question Help * Adrug s ordered to bdinitorod I at hmin, and muyincremso by 5 mulimin q 15 min tb a max of 2a Construct the first two lines of the titration table for this order. mumin. The ? strength is 10mumL O A. Dose Rate (mU/min) IV rate (mUh 3 mU/min (initial) 8 mU/mirn 18 mUh 48 mL/h Dose Rate (mU/min) IV rate (mLn) 3 mU/min (initial) 18 mUh 48 mL/h OC. Dose Rate (mU/min) IV rate (mLD) 12 mL/h 8 mU/min 3 mU/min (initial) 8 mU/min 18 mLh 36 mUh

Explanation / Answer

initial dose= 3 mU/min

here,

the order is to increase the dose by 5 mU/ min in every 15 minutes

so, after 15 minutes, dose become

3+5 = 8 mU/min(5 mU added with initial dose)

given, 1ml = 10 mU

the initial dose is only 3mU/min

so ml/min in initial dose = 3/10= 0.3ml/min

flow rate = 0.3 *60(since, 0.3ml for a minute)= 18 ml/hr

after increase of 5 mU/min in 15 min dose becomes 8 mU/min

so, ml/min= 8/10=0.8ml/min

covert it into hour

thus, flow rate for 1 hour=0.8* 60=48 ml/hr

so, the titration will be

3 mU/min(initial) -18 mL/h

8 mU/min -48mL/h

answer= A

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