You are outside at 7:30pm doing homework on August 30, 2016. You are supposed to
ID: 236964 • Letter: Y
Question
You are outside at 7:30pm doing homework on August 30, 2016. You are supposed to locate Mars in the sky when your friend texts you. She says that she cannot go outside to look until 11pm. She asks you were she should look at 11pm. You carefully measure the azimuth of Mars to be 194.2617 degrees and the altitude to be 28.2584 deg using the compass and level apps on your phone. sidereal time is 17:42:10. latitude and longitude are 248°20'12''E, 35°12'07''N
a) what is Mars' apparent RA and Dec
b) Using the RA and Dec what will be the altitude and azimuth of Mars at 11pm
c) if looking from latitude and longitude 281°30'27.0''E, 0°14'00.6''S at same time, what what altitude and azimuth should we look. (compute the Sidereal Time by comparing previous longitude to this one)
Forumulas given:
Explanation / Answer
answer- 1 at 7:30 Pm azimuth of mars is 194,276 degree and altitude is 28.2584 degree.
the siderak time is about 17:42:10 and longitude is 248,20'12'' E and latidue is 35. 12'07'' N
answer- the ra (right ascension) is 16h 45m 42.6s
and the dec (Declination) is 025° 06' 12.9"
Answer 2- at 11:30 PM
the apparent Ra (right ascension) of moon is 16h 45m 55.0s
the apparent dec (declination) of moon is 025° 06' 32.9"
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