In our class thought experiment isobarically boiling water, we saw that the liqu

Question

In our class thought experiment isobarically boiling water, we saw that the liquid phase is almost incompressible. More precisely, the specific volume of the liquid at a given temperature doesn't change appreciably near the vapor pressure curve from the saturated liquid specific volume. In the absence of compressed liquid data, one approximates the the specific volume of a compressed liquid at a given T by V_f. What is the specific volume of water at 20degree C and 100 kPa? Check: The specific volume of R-134a at p = 970 kPa and T = 38degree C is approximately 0.0008657 m^3/kg

Explanation / Answer

>> As, at P = 100 kPa ,

Seeing from Steam Table,

Tsat = 100°C

But, here T = 20°C is less than Tsat

>> At, saturation specific volume, vf = 0.001043 m3/Kg

So, Specific Volume at Given State , v = 0.001043 m3/Kg ..... ANSWER....

Checking for R134a

At P = 970 kPa

Seeing from Property Table of R134a,

Tsat = 38. 24°C

So, our given state is almost at saturated liquid state

So, Specific Volume = vf  = 0.0008657 m3/Kg...

Thus, it is true.....

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