On the basis of the average temperature gradient of the in the situations below,
ID: 231826 • Letter: O
Question
On the basis of the average temperature gradient of the in the situations below, classify the degree of stability (unstable, neutral, or stable) of the atmosphere:
Temperature at ground level is 70o F and the temperature at 1500 feet is 80o F.
Temperature at ground-level is 25o C and the temperature at 700m is 28o C.
Determine the temperature gradient for each part of question 2 above.
The ground level wind velocity at 10 m elevation is 7mi/hr. in a city. What would you estimate the velocity to be at 100-m elevation, in miles per hour, based upon Table 3-3, if there is a B stability class?Table 3-3 ; Value of Exponent, p, in equation (3-13)
Stability Category
Rural exponent
Urban exponent
A
0.07
0.15
B
0.07
0.15
C
0.10
0.20
D
0.15
0.25
E
0.35
0.30
F
0.55
0.30
Stability Category
Rural exponent
Urban exponent
A
0.07
0.15
B
0.07
0.15
C
0.10
0.20
D
0.15
0.25
E
0.35
0.30
F
0.55
0.30
Explanation / Answer
1) a) Temperature at ground level is 70o F
Temperature at 1500 feet is 80o F
Temperature gradient= 80-70/(1500-0)= 10/1500=0.0066oF/feet
This condition is stable.
b) Temperature at ground-level is 25o C
Temperature at 700m is 28o C
Temperature gradient= 28-25/(700-0)=0.0016oC/m
This condition is stable.
2) U2 = U1 * ( Z2/Z1)p
B- Moderately Unstable
If there is a B stability (ie moderately stable), the velocity at 100-m elevation is:
In the Rural areas, U2= 8.22mi/hr
In the Urban areas, U2= 9.89mi/hr
Stability Category Rural exponent-p u2-mi/hr Urban exponent-p u2-mi/hr A- Very Unstable, 0.07 8.22 0.15 9.89B- Moderately Unstable
0.07 8.22 0.15 9.89 C-Slightly Unstable 0.10 8.812 0.20 11.09 D- Neutral 0.15 9.89 0.25 12.45 E- Moderately Stable 0.35 15.67 0.30 13.97 F- Very Stable 0.55 24.84 0.30 13.97Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.