Q1: The surface of a conductor and gaussian surface can be seen in figure. Q2: E

Question

Q1: The surface of a conductor and gaussian surface can be seen in figure. Q2: Electric field intensity at inner surface of conductor is greater than electric field intensity at the outer surface of conductor, it can be seen in the figure. But how the potential is equal from inner surface to outer surface? ( inside of conductor E=0 that's OK. But i did not understant how the potential at outer surface is equal to potential at inner surface)
Thank you. Free space AS Ps 4 w, in terface. a in Conductor (E-)

Explanation / Answer

https://www.dropbox.com/s/0stkhkda0n2qr0c/237.jpg?dl=0

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